Help!

Point E placed at line AD. AE = CE = 16 cm and DE = 8 cm.
How big angle ABC?
Kinda hard for me.

I've tried Pythagoras' Theorem and the laws of sine, cosine and tangent, yet I can't find a clue.
I'll try to ask my friend for help.

hmm....if only they gave angle DCE and angle C. then you can make an angle bisector line from angle C to line AB, we can call point F. then you can subract 90 degrees plus the angle BCF from 180 and you can get the angle of B.

But other than that, I see no other way....can't you ask your teacher? Whenever I dont get something on my math homework, I ask my teacher the next day and he always explains it and sorry for the late responses, its prolly midnight there in Indonesia

AHH VIRUS! oh wait, that's just a math problem.

I hear ya, I hate geometry. I took 2 practice math portions of an ACT test (US college-prep analyzer/aptitude test) and got sub-20's out of 60. not good.

I asked one of my friend and he too ask another of his friend. Both of them couldn't solve it.

If Line AB was given, I could have solve it by now.

I read AB = BC.
If none know it, I'll ask my teacher. Anyway thanks for everyone.

Okay - I've been looking at this for an hour now and I can't figure it out. There is a crucial piece of information missing.

My advice is to go to your teacher, explain that you cannot solve it and ask him to guide you through it.

, just see what's on the angle mesurer!

Blakeway - it's not to scale.

I know, I was kidding...

I've got Alg II and I can't help you... Sorry

I got it!
Because CE = 2DE so <CED = 60 degree. It's (maybe) Triple Pytagoras(90,60,30). Angle CEA = 180 - <CED =120. <CEA + <CBA = 180. <CBA = 60.